Movement and Position
4 marks · EasyAn object starts from rest and accelerates uniformly at 2 m/s² for 6 s.
Calculate the final velocity of the object.
Calculate the distance travelled by the object during this time using the area under the velocity–time graph.
Work this out on paper, then compare with the answer and worked solution below. With a free account you can submit written answers for marking.
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(a) 12 m/s
(b) 36 m
Common mistakes: Using u instead of v for area
Show mark scheme and worked solution
Marking points
M1 (a) · 1 mark · Uses v = u + at with correct values
A1 (a) · 1 mark · 12 m/s
M2 (b) · 1 mark · Area under v–t graph = (1/2 × base × height)
A2 (b) · 1 mark · Correct answer 36 m (follow-through)
Worked solution
a) Final velocity v = u + at = 0 + (2 × 6) = 12 m/s
b) Distance = area under v–t graph = ½ × base × height = ½ × 6 × 12 = 36 m