Area under a velocity-time graph gives distance travelled
2 marks · NormalA cyclist moves at a constant velocity of 6 m/s for 35 seconds. Calculate the distance travelled using the area under the velocity–time graph.
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210 m (±1)
Must show: Multiplies velocity by time
Common mistakes: Dividing instead of multiplying; Confusing velocity with acceleration
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Marking points
M1 · 1 mark · Identifies area under graph as rectangle and uses distance = velocity × time.
A1 · 1 mark · Gives correct answer: 210 m (accept 209–211).
Worked solution
Distance = area under the graph = velocity × time = 6 m/s × 35 s = 210 m