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Question 67 of 97 in Movement and Position

Area under a velocity-time graph gives distance travelled

3 marks · Normal

The graph shows the motion of a car as it accelerates uniformly from rest to 18 m/s in 6 seconds.

line graph of Velocity (m/s) against Time (s)0123456702468101214161820Time (s)Velocity (m/s)
Figure 2. Velocity-time graph for a car accelerating
(a)

Calculate the total distance the car travels in the first 6 seconds.

[2 marks]
(b)

State the shape formed under the graph and briefly describe how you found the distance.

[1 mark]

Work this out on paper, then compare with the answer and worked solution below. With a free account you can submit written answers for marking.

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(a) 54 m · must show Area = ½ × 6 × 18

(b) The shape is a triangle. The distance is the area of the triangle: ½ × base × height. · must show States 'triangle', Mentions area formula

Must show: Area calculated using correct formula

Common mistakes: Calculating rectangle, not triangle; Forgetting to halve the product

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Marking points

M1 (a) · 1 mark · Uses correct area formula: ½ × base × height.

A1 (a) · 1 mark · Gives correct answer: 54 m (accept 53–55).

B1 (b) · 1 mark · States shape under the graph is a triangle and links to area calculation.

Worked solution

a) Area = ½ × base × height = ½ × 6 s × 18 m/s = 54 m.

b) The shape is a triangle. I found the distance by calculating the area of the triangle under the graph.

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