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Question 15 of 249 in Electricity

MAINS ELECTRICITY

4 marks · Normal

A hairdryer is connected to the mains. The diagram shows a simplified circuit with a fuse.

Series circuit: cell, wire, lamp, wire, resistorMains supply (230 V)Heating elementFuse
(a)

Name two energy transfers that take place when the hairdryer is used.

[2 marks]
(b)

Explain what happens to the fuse if the heating element develops a short circuit.

[2 marks]

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(a) Electrical energy is transferred to thermal (heat) energy and to kinetic energy (if the hairdryer has a fan).

(b) A short circuit causes a large current to flow through the fuse, which then heats up and melts, breaking the circuit.

Must show: energy transfer terms, current/fuse relationship

Also accept: Electrical -> thermal, electrical -> kinetic (fan)

Common mistakes: Wrong order of energy, omitting fuse explanation

Show mark scheme and worked solution

Marking points

B1 (a) · 1 mark · States electrical energy is converted to thermal (heat) energy.

B1 (a) · 1 mark · States electrical energy is converted to kinetic energy or vice versa.

M1 (b) · 1 mark · States that a large current flows if there is a short circuit.

A1 (b) · 1 mark · Explains the fuse melts/breaks the circuit to prevent damage or further hazard.

Worked solution

a) Electrical energy is transferred to heat energy (to dry hair) and to kinetic energy (the fan inside the hairdryer spins to blow air).

b) If a short circuit develops, the current through the fuse increases greatly. The fuse wire heats up and melts, disconnecting the circuit and preventing further damage or hazard.

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