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Question 16 of 16 in Describing waves

Describing waves

4 marks · Normal

The graph below shows the displacement of a point in a wave against time.

line graph of Displacement/cm (cm) against Time/s (s)01234-5-4-3-2-1012345Time/s (s)Displacement/cm (cm)
Wave displacement vs time
(a)

State the amplitude of the wave.

[1 mark]
(b)

Determine the time period of the wave.

[2 marks]
(c)

Calculate the frequency.

[1 mark]

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(a) 5 cm

(b) 2 s

(c) 0.5 Hz

Show mark scheme and worked solution

Marking points

B1 (a) · 1 mark · States amplitude as 5 cm (max displacement on y-axis).

M1 (b) · 1 mark · Measures period as time for one full cycle (e.g., 0 to 2 seconds).

A1 (b) · 1 mark · Gives correct time period: 2 s.

B2 (c) · 1 mark · Calculates frequency: 1/period = 0.5 Hz.

Worked solution

a) Amplitude is the maximum positive or negative displacement: 5 cm.

b) From t = 0 to t = 2 s is one cycle, so period T = 2 s.

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