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Question 15 of 18 in Power

Power

3 marks · Normal

A table shows the time taken for four students to lift identical boxes through the same vertical distance:

StudentTime taken (s)
Ali10
Ben8
Chloe12
Dina6

Each box requires 300 J of work to be lifted.

(a)

Which student had the greatest power output?

[1 mark]
(b)

Calculate the power output for this student.

[2 marks]

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(a) Dina

(b) 50 W

Common mistakes: Picking student with least power by mistake; Not using correct formula

Show mark scheme and worked solution

Marking points

B1 (a) · 1 mark · Identifies Dina as the student with the greatest power (shortest time)

M1 (b) · 1 mark · Uses P = W / t with Dina's time (6 s) (follow-through)

A1 (b) · 1 mark · Correct final answer with unit (50 W, or correct follow-through) (follow-through)

Worked solution

a) Dina took the least time, so had the highest power output.

b) Power = work / time = 300 J / 6 s = 50 W.

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