Question 248 of 279 in Solids, Liquids and Gases

Absolute zero

1 mark · Easy

A scientist cools a gas sample to -10 °C. What is this temperature in Kelvin?

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263 K (±0)

Common mistakes: 283 K; -10 K

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Marking points

A1 · 1 mark · Correctly converts -10 °C to 263 K (accept working shown).

Worked solution

T(K) = T(°C) + 273 = -10 + 273 = 263 K

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