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Question 204 of 356 in Waves

Properties of Waves

4 marks · Normal

The graph below shows the displacement of a point on a string as a wave passes along it.

Displacement of a point on a string over time00.010.020.030.04-10-50510Time (s) (s)Displacement (mm) (mm)Displacement of a point on a string over time
Wave displacement versus time
(a)

What is the amplitude of the wave shown on the graph?

[1 mark]
(b)

Determine the time period of the wave.

[1 mark]
(c)

Calculate the frequency of the wave.

[2 marks]

Work this out on paper, then compare with the answer and worked solution below. With a free account you can submit written answers for marking.

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(a) 10 mm · must show correct reading of amplitude

(b) 0.04 s · must show period from two identical points

(c) 25 Hz · must show f=1/T, frequency calculation

Common mistakes: Halving the amplitude; Incorrectly reading the period

Show mark scheme and worked solution

Marking points

A1 (a) · 1 mark · States amplitude is 10 mm.

A2 (b) · 1 mark · States period is 0.04 s.

M1 (c) · 1 mark · Uses f = 1/T formula.

A3 (c) · 1 mark · Correct frequency (25 Hz). (follow-through)

Worked solution

a) The amplitude is the maximum displacement from zero, which is 10 mm.

b) The time for one complete cycle (from 0 to 0) is 0.04 s.

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