Practical: investigate the specific heat capacity of a substance
4 marks · NormalA student records the following data in a specific heat capacity experiment on a 0.30 kg block of material:
| Quantity | Reading |
|---|---|
| Initial temperature / °C | 18 |
| Final temperature / °C | 34 |
| Voltage / V | 12 |
| Current / A | 3.5 |
| Time / s | 200 |
Calculate the change in temperature of the block.
Calculate the energy supplied by the heater.
Use your answers to calculate the specific heat capacity of the material.
Work this out on paper, then compare with the answer and worked solution below. With a free account you can submit written answers for marking.
Show answer
(a) 16 °C
(b) 8,400 J
(c) 1,750 J/kg °C
Common mistakes: Incorrect subtraction for Δθ; Unit confusion for energy; Forgetting to convert mass to kg
Show mark scheme and worked solution
Marking points
B1 (a) · 1 mark · Correctly finds Δθ = final temperature - initial temperature
M1 (b) · 1 mark · Substitutes values into Q = V × I × t
A1 (b) · 1 mark · Correct value for energy supplied (8,400 J)
A2 (c) · 1 mark · Correct answer for c (1,750 J/kg °C) with correct substitution and units (follow-through)
Worked solution
a) Change in temperature Δθ = final temperature − initial temperature
b) Q = V × I × t
c) c = Q / (m × Δθ)