Area under a velocity-time graph gives distance travelled
2 marks · EasyAn object starts from rest and accelerates uniformly to 10 m/s in 5 seconds. Calculate the distance it travels during this time using the area under the velocity–time graph.
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25 m (±0.5)
Common mistakes: Using wrong formula; Using 5×10 instead of 0.5×5×10
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Marking points
M1 · 1 mark · Uses correct formula for area of triangle: 0.5 × base × height.
A1 · 1 mark · Calculates 25 m correctly.
Worked solution