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Question 52 of 122 in Properties of Waves

Describing waves

4 marks · Normal

A loudspeaker produces a sound wave with a frequency of 450 Hz. Each wave has a time period of 0.0022 seconds.

(a)

State the equation relating frequency and time period for a wave.

[1 mark]
(b)

Using the equation, calculate the frequency expected if the time period is 0.0022 s.

[2 marks]
(c)

Suggest why the calculated frequency and measured frequency might not match exactly.

[1 mark]

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(a) f = 1/T

(b) f = 1/0.0022 = 454.5 Hz

(c) Any correct suggestion, e.g. measurement errors or rounding in the values used.

Must show: correct equation, correct calculation steps, any valid reason for mismatch

Common mistakes: Using T = f × t instead of T = 1/f

Show mark scheme and worked solution

Marking points

B1 (a) · 1 mark · States correct equation: f = 1/T.

M1 (b) · 1 mark · Substitutes: 1 / 0.0022 or equivalent, or correct working seen.

A1 (b) · 1 mark · Evaluates answer correctly: 454.5 Hz (accept any value in range 454–455 Hz). (follow-through)

B1 (c) · 1 mark · Gives a correct reason for a difference (e.g. measurement error, rounding, instrument precision).

Worked solution

a) The equation is f = 1/T.

b) f = 1 / (0.0022 s) = 454.5 Hz.

c) The calculated and measured values might not match due to errors in measuring time period, rounding, or the limits of the measurement equipment.

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