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Question 18 of 18 in Power

Power

5 marks · Hard

A 0.25 kg ball is dropped from a balcony 25 m above the ground. Ignore air resistance.

(a)

Calculate the gravitational potential energy lost by the ball as it falls.

[2 marks]
(b)

Determine the speed of the ball just before it hits the ground.

[2 marks]
(c)

Explain why, in real life, the ball’s speed might be less than your calculation.

[1 mark]

Work this out on paper, then compare with the answer and worked solution below. With a free account you can submit written answers for marking.

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(a) 62.5 J

(b) 22.4 m/s

(c) Air resistance does work on the ball, converting some energy to heat, so not all GPE is converted to KE.

Common mistakes: Not using correct significant figures; Leaving answer in wrong units; Forgetting to take square root when finding speed

Show mark scheme and worked solution

Marking points

M1 (a) · 1 mark · Uses GPE = mgh with correct values.

A1 (a) · 1 mark · Calculates GPE lost: 62.5 J.

M2 (b) · 1 mark · Sets KE = GPE lost, uses . (follow-through)

A2 (b) · 1 mark · Correct final speed: 22.4 m/s. (follow-through)

B1 (c) · 1 mark · States that air resistance means not all GPE is transferred to KE (energy dissipated).

Worked solution

(a) GPE lost = mgh

(b) Assuming all GPE is converted to KE just before hitting the ground:

(c) In real life, the ball will experience air resistance which transfers some energy to the surroundings as heat, so not all the lost GPE is converted into kinetic energy.

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