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Question 65 of 69 in Units (Solids, Liquids and Gases)

Units (Solids, Liquids and Gases)

4 marks · Easy

A diver descends in the sea to a depth of 15 m. The density of seawater is 1025 kg/m³. Take gravitational field strength g = 10 N/kg.

(a)

Calculate the increase in pressure on the diver at this depth, relative to the surface.

[2 marks]
(b)

Describe how pressure in a liquid acts on the diver at this depth.

[1 mark]
(c)

Explain how the force on a part of the diver’s body can be calculated using pressure and area.

[1 mark]

Work this out on paper, then compare with the answer and worked solution below. With a free account you can submit written answers for marking.

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(a) 153,750 Pa

(b) Pressure in a liquid acts equally in all directions.

(c) Force can be calculated using F = p × A, where A is the area of the body part.

Common mistakes: using wrong values in formula; incorrect units

Show mark scheme and worked solution

Marking points

M1 (a) · 1 mark · Writes correct formula and substitutes: p = h x ρ x g = 15 x 1025 x 10.

A1 (a) · 1 mark · Correct final answer: 153,750 Pa with correct unit. (follow-through)

B1 (b) · 1 mark · States that pressure acts equally in all directions in a non-moving fluid.

B2 (c) · 1 mark · Correct statement that force equals pressure multiplied by area, with formula F = p × A or equivalent.

Worked solution

a) Pressure difference:

b) In liquids, pressure acts equally in all directions at a given depth when stationary.

c) The force on a surface is calculated using F = p × A, where A is the area of the surface.

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