Pearson Edexcel International GCSE (9–1) · CHEMISTRY · Section
Concentrations of solutions
19 practice questions
Practice questions
1–8 of 8 · Normal
Question 1
2 marks · Normal
Answer and see the solution →A solution contains 4.0 g of potassium chloride (KCl) dissolved in exactly 100 cm³ of water. Calculate the concentration of this solution in g/dm³.
Question 2
4 marks · Normal
Answer and see the solution →(a)[1 mark]Give the formula that links concentration in mol/dm³, amount in mol, and volume in dm³.
(b)[1 mark]A student dissolves 2.5 g of magnesium sulfate (MgSO₄, Ar: Mg = 24, S = 32, O = 16) in 200 cm³ of water.
i. Calculate the number of moles of MgSO₄ in the solution.
(c)[2 marks]ii. Calculate the concentration of MgSO₄ in mol/dm³ in the solution.
Question 3
3 marks · Normal
Answer and see the solution →Calculate the mass of sodium nitrate (NaNO₃, Ar: Na = 23, N = 14, O = 16) required to make 250 cm³ of a 0.050 mol/dm³ solution.
Question 4
3 marks · Normal
Answer and see the solution →A teacher claims that doubling the amount of solute added to a fixed volume of water will always double the concentration of the solution. Explain using calculations and an example whether this statement is correct.
Question 5
4 marks · Normal
Answer and see the solution →Concentration and volume data for sodium sulfate solutions Sample Concentration (mol/dm³) Volume used (dm³) A 0.10 0.020 B 0.20 0.015 C 0.40 0.025 (a)[2 marks]Which sample contains the largest amount of sodium sulfate? Show your calculations.
(b)[1 mark]State the amount in mol present in that sample.
(c)[1 mark]Suggest one reason why a higher concentration solution may have less sodium sulfate than a lower concentration solution.
Question 6
1 mark · Normal
Answer and check →Which calculation gives the concentration, in mol/dm³, of a solution containing 1.5 mol of solute in 0.75 dm³ of solution?
- A.1.5 ÷ 0.75
- B.0.75 ÷ 1.5
- C.1.5 × 0.75
- D.0.75 × 1.5
Question 7
2 marks · Normal
Answer and see the solution →Calculate the concentration in mol/dm³ of a solution containing 5.60 g of potassium hydroxide (KOH, Ar: K = 39, O = 16, H = 1) in 500 cm³ of solution.
Question 8
4 marks · Normal
Answer and see the solution →(a)[2 marks]A solution has a concentration of 1.5 mol/dm³. What is the amount (in mol) of solute in 750 cm³ of this solution?
(b)[2 marks]Describe how you would prepare 750 cm³ of this solution from a 3.0 mol/dm³ solution.