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Pearson Edexcel International GCSE (9–1) · CHEMISTRY · Section

The electrolysis of copper(ii) sulfate solution using inert electrodes

18 practice questions

Practice questions

1–7 of 7 · Easy

  1. Question 1

    1 mark · Easy

    State the product formed at the cathode during the electrolysis of copper(II) sulfate solution using inert electrodes.

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  2. Question 2

    2 marks · Easy

    The reactivity series places copper below hydrogen. Using this fact and your knowledge of ions in copper(II) sulfate solution, explain why copper is deposited at the cathode and not hydrogen during electrolysis with inert electrodes.

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  3. Question 3

    2 marks · Easy

    Describe how a sample of copper(II) sulfate solution would be different after it is electrolysed for a long time using inert electrodes.

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  4. Question 4

    3 marks · Easy

    The table below shows the ions present in copper(II) sulfate solution before and after electrolysis with inert electrodes.

    IonBefore electrolysisAfter prolonged electrolysis
    Cu^{2+}PresentAbsent
    SO_4^{2-}PresentPresent
    H^+PresentPresent
    OH^-PresentAbsent

    From the table, state which ion is responsible for the product formed at the cathode, and name the product.

    From the table, state which ion is responsible for the product formed at the anode, and name the product.

    Using your answers, give the overall effect of electrolysis on the copper(II) sulfate solution.

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  5. Question 5

    1 mark · Easy

    Write the balanced half-equation for the reaction at the cathode during the electrolysis of copper(II) sulfate solution using inert electrodes.

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  6. Question 6

    3 marks · Easy

    Explain why oxygen is produced at the anode and not sulfate ions are discharged during the electrolysis of copper(II) sulfate solution with inert electrodes.

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  7. Question 7

    2 marks · Easy

    If all the copper(II) ions are removed from 100 mL of copper(II) sulfate solution by electrolysis with inert electrodes, explain and calculate what type of ions are left in the solution and what the new solution is.

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