Pearson Edexcel International GCSE (9–1) · PHYSICS · Section
Absolute zero
16 practice questions
Practice questions
1–8 of 8 · Normal
Question 1
4 marks · Normal
Answer and see the solution →The diagram shows a pressure gauge connected to a sealed rigid container filled with air. The container is placed in a cold room and the temperature is monitored.
(a)[1 mark]State what is meant by absolute zero.
(b)[1 mark]The initial temperature of the air is 15 °C. Calculate the temperature in Kelvin.
(c)[1 mark]If the temperature falls to -40 °C, calculate the new temperature in Kelvin.
(d)[1 mark]Explain why the pressure in the container decreases as the temperature falls, referencing ideas about energy of gas particles.
Question 2
3 marks · Normal
Answer and see the solution →A sample of gas is heated from -15 °C to 65 °C at constant volume. The initial pressure is 80 kPa.
Calculate the final pressure of the gas in kPa. Show all your steps and give your answer to 2 significant figures.
Question 3
1 mark · Normal
Answer and see the solution →Room temperature is 25 °C. What is this temperature in kelvin?
Question 4
2 marks · Normal
Answer and see the solution →Explain what happens to the kinetic energy of particles as a substance approaches absolute zero.
Question 5
1 mark · Normal
Answer and check →Which temperature is closest to absolute zero?
- A.0 °C
- B.-273 °C
- C.273 K
- D.100 K
Question 6
3 marks · Normal
Answer and see the solution →A physics classroom is at 18 °C. A scientist is cooling a gas sample to investigate pressure at lower temperatures.
(a)[1 mark]Convert the classroom temperature to kelvin.
(b)[1 mark]The gas is cooled to 5 °C. What is this temperature in kelvin?
(c)[1 mark]If the gas were cooled to 0 K, what would happen to the motion of the particles? Explain.
Question 7
2 marks · Normal
Answer and see the solution →Why must you convert temperatures to kelvin before using gas law equations?
Question 8
1 mark · Normal
Answer and see the solution →A student writes this formula for converting celsius to kelvin:
T_kelvin = T_celsius + 273